Subsetting Data

Last updated on 2024-10-16 | Edit this page

Overview

Questions

How can I work with subsets of data in R?

Objectives

To be able to subset vectors and data frames
To be able to extract individual and multiple elements: by index, by name, using comparison operations
To be able to skip and remove elements from various data structures.

R has many powerful subset operators. Mastering them will allow you to easily perform complex operations on any kind of dataset.

There are six different ways we can subset any kind of object, and three different subsetting operators for the different data structures.

Let’s start with the workhorse of R: a simple numeric vector.

R

x <- c(5.4, 6.2, 7.1, 4.8, 7.5)
names(x) <- c('a', 'b', 'c', 'd', 'e')
x

OUTPUT

  a   b   c   d   e
5.4 6.2 7.1 4.8 7.5

Atomic vectors

In R, simple vectors containing character strings, numbers, or logical values are called atomic vectors because they can’t be further simplified.

So now that we’ve created a dummy vector to play with, how do we get at its contents?

Accessing elements using their indices

To extract elements of a vector we can give their corresponding index, starting from one:

R

x[1]

OUTPUT

  a
5.4

R

x[4]

OUTPUT

  d
4.8

It may look different, but the square brackets operator is a function. For vectors (and matrices), it means “get me the nth element”.

We can ask for multiple elements at once:

R

x[c(1, 3)]

OUTPUT

  a   c
5.4 7.1

Or slices of the vector:

R

x[1:4]

OUTPUT

  a   b   c   d
5.4 6.2 7.1 4.8

the : operator creates a sequence of numbers from the left element to the right.

R

1:4

OUTPUT

[1] 1 2 3 4

R

c(1, 2, 3, 4)

OUTPUT

[1] 1 2 3 4

We can ask for the same element multiple times:

R

x[c(1, 1, 3)]

OUTPUT

  a   a   c
5.4 5.4 7.1

If we ask for an index beyond the length of the vector, R will return a missing value:

R

x[6]

OUTPUT

<NA>
  NA

This is a vector of length one containing an NA, whose name is also NA.

If we ask for the 0th element, we get an empty vector:

R

x[0]

OUTPUT

named numeric(0)

Vector numbering in R starts at 1

In many programming languages (C and Python, for example), the first element of a vector has an index of 0. In R, the first element is 1.

Skipping and removing elements

If we use a negative number as the index of a vector, R will return every element except for the one specified:

R

x[-2]

OUTPUT

  a   c   d   e
5.4 7.1 4.8 7.5

We can skip multiple elements:

R

x[c(-1, -5)]  # or x[-c(1,5)]

OUTPUT

  b   c   d
6.2 7.1 4.8

Tip: Order of operations

A common trip up for novices occurs when trying to skip slices of a vector. It’s natural to to try to negate a sequence like so:

R

x[-1:3]

This gives a somewhat cryptic error:

ERROR

Error in x[-1:3]: only 0's may be mixed with negative subscripts

But remember the order of operations. : is really a function. It takes its first argument as -1, and its second as 3, so generates the sequence of numbers: c(-1, 0, 1, 2, 3).

The correct solution is to wrap that function call in brackets, so that the - operator applies to the result:

R

x[-(1:3)]

OUTPUT

  d   e
4.8 7.5

To remove elements from a vector, we need to assign the result back into the variable:

R

x <- x[-4]
x

OUTPUT

  a   b   c   e
5.4 6.2 7.1 7.5

Challenge 1

Given the following code:

R

x <- c(5.4, 6.2, 7.1, 4.8, 7.5)
names(x) <- c('a', 'b', 'c', 'd', 'e')
print(x)

OUTPUT

  a   b   c   d   e
5.4 6.2 7.1 4.8 7.5

Come up with at least 3 different commands that will produce the following output:

OUTPUT

  b   c   d
6.2 7.1 4.8

After you find 3 different commands, compare notes with your neighbour. Did you have different strategies?

Solution to challenge 1

R

x[2:4]

OUTPUT

  b   c   d
6.2 7.1 4.8

R

x[-c(1,5)]

OUTPUT

  b   c   d
6.2 7.1 4.8

R

x[c("b", "c", "d")]

OUTPUT

  b   c   d
6.2 7.1 4.8

R

x[c(2,3,4)]

OUTPUT

  b   c   d
6.2 7.1 4.8

Subsetting by name

We can extract elements by using their name, instead of extracting by index:

R

x <- c(a = 5.4, b = 6.2, c = 7.1, d = 4.8, e = 7.5) # we can name a vector 'on the fly'
x[c("a", "c")]

OUTPUT

  a   c
5.4 7.1

This is usually a much more reliable way to subset objects: the position of various elements can often change when chaining together subsetting operations, but the names will always remain the same!

Subsetting through other logical operations

We can also use any logical vector to subset:

R

x[c(FALSE, FALSE, TRUE, FALSE, TRUE)]

OUTPUT

  c   e
7.1 7.5

Since comparison operators (e.g. >, <, ==) evaluate to logical vectors, we can also use them to succinctly subset vectors: the following statement gives the same result as the previous one.

R

x[x > 7]

OUTPUT

  c   e
7.1 7.5

Breaking it down, this statement first evaluates x>7, generating a logical vector c(FALSE, FALSE, TRUE, FALSE, TRUE), and then selects the elements of x corresponding to the TRUE values.

We can use == to mimic the previous method of indexing by name (remember you have to use == rather than = for comparisons):

R

x[names(x) == "a"]

OUTPUT

  a
5.4

Tip: Combining logical conditions

We often want to combine multiple logical criteria. For example, we might want to find all the countries that are located in Asia or Europe and have life expectancies within a certain range. Several operations for combining logical vectors exist in R:

&, the “logical AND” operator: returns TRUE if both the left and right are TRUE.
|, the “logical OR” operator: returns TRUE, if either the left or right (or both) are TRUE.

You may sometimes see && and || instead of & and |. These two-character operators only look at the first element of each vector and ignore the remaining elements. In general you should not use the two-character operators in data analysis; save them for programming, i.e. deciding whether to execute a statement.

!, the “logical NOT” operator: converts TRUE to FALSE and FALSE to TRUE. It can negate a single logical condition (eg !TRUE becomes FALSE), or a whole vector of conditions(eg !c(TRUE, FALSE) becomes c(FALSE, TRUE)).

Additionally, you can compare the elements within a single vector using the all function (which returns TRUE if every element of the vector is TRUE) and the any function (which returns TRUE if one or more elements of the vector are TRUE).

Challenge 2

Given the following code:

R

x <- c(5.4, 6.2, 7.1, 4.8, 7.5)
names(x) <- c('a', 'b', 'c', 'd', 'e')
print(x)

OUTPUT

  a   b   c   d   e
5.4 6.2 7.1 4.8 7.5

Write a subsetting command to return the values in x that are greater than 4 and less than 7.

Solution to challenge 2

R

x_subset <- x[x<7 & x>4]
print(x_subset)

OUTPUT

  a   b   d
5.4 6.2 4.8

Tip: Getting help for operators

Remember you can search for help on operators by wrapping them in quotes: help("%in%") or ?"%in%".

Handling special values

At some point you will encounter functions in R that cannot handle missing, infinite, or undefined data.

There are a number of special functions you can use to filter out this data:

is.na will return all positions in a vector, matrix, or data frame containing NA (or NaN)
likewise, is.nan, and is.infinite will do the same for NaN and Inf.
is.finite will return all positions in a vector, matrix, or data.frame that do not contain NA, NaN or Inf.
na.omit will filter out all missing values from a vector

Data frames

Remember the data frames are lists underneath the hood, so similar rules apply. However they are also two dimensional objects:

[ with one argument will act the same way as for lists, where each list element corresponds to a column. The resulting object will be a data frame:

R

head(gapminder[3])

OUTPUT

Similarly, [[ will act to extract a single column:

R

head(gapminder[["lifeExp"]])

OUTPUT

[1] 28.801 30.332 31.997 34.020 36.088 38.438

And $ provides a convenient shorthand to extract columns by name:

R

head(gapminder$year)

OUTPUT

[1] 1952 1957 1962 1967 1972 1977

To select specific rows and/or columns, you can provide two arguments to [

R

gapminder[1:3, ]

OUTPUT

      country year      pop continent lifeExp gdpPercap
1 Afghanistan 1952  8425333      Asia  28.801  779.4453
2 Afghanistan 1957  9240934      Asia  30.332  820.8530
3 Afghanistan 1962 10267083      Asia  31.997  853.1007

If we subset a single row, the result will be a data frame (because the elements are mixed types):

R

gapminder[3, ]

OUTPUT

      country year      pop continent lifeExp gdpPercap
3 Afghanistan 1962 10267083      Asia  31.997  853.1007

But for a single column the result will be a vector (this can be changed with the third argument, drop = FALSE).

Challenge 3

Fix each of the following common data frame subsetting errors:

Extract observations collected for the year 1957

R

gapminder[gapminder$year = 1957, ]

Extract all columns except 1 through to 4

R

gapminder[, -1:4]

Extract the rows where the life expectancy is longer the 80 years

R

gapminder[gapminder$lifeExp > 80]

Extract the first row, and the fourth and fifth columns (lifeExp and gdpPercap).

R

gapminder[1, 4, 5]

Advanced: extract rows that contain information for the years 2002 and 2007

R

gapminder[gapminder$year == 2002 | 2007,]

Solution to challenge 3

Fix each of the following common data frame subsetting errors:

Extract observations collected for the year 1957

R

# gapminder[gapminder$year = 1957, ]
gapminder[gapminder$year == 1957, ]

Extract all columns except 1 through to 4

R

# gapminder[, -1:4]
gapminder[,-c(1:4)]

Extract the rows where the life expectancy is longer the 80 years

R

# gapminder[gapminder$lifeExp > 80]
gapminder[gapminder$lifeExp > 80,]

Extract the first row, and the fourth and fifth columns (lifeExp and gdpPercap).

R

# gapminder[1, 4, 5]
gapminder[1, c(4, 5)]

Advanced: extract rows that contain information for the years 2002 and 2007

R

# gapminder[gapminder$year == 2002 | 2007,]
gapminder[gapminder$year == 2002 | gapminder$year == 2007,]
gapminder[gapminder$year %in% c(2002, 2007),]

Challenge 4

Why does gapminder[1:20] return an error? How does it differ from gapminder[1:20, ]?
Create a new data.frame called gapminder_small that only contains rows 1 through 9 and 19 through 23. You can do this in one or two steps.

Solution to challenge 4

gapminder is a data.frame so it needs to be subsetted on two dimensions. gapminder[1:20, ] subsets the data to give the first 20 rows and all columns.

R

gapminder_small <- gapminder[c(1:9, 19:23),]

Key Points

Indexing in R starts at 1, not 0.
Access individual values by location using [].
Access slices of data using [low:high].
Access arbitrary sets of data using [c(...)].
Use logical operations and logical vectors to access subsets of data.